Q:

Truck drivers report the mileage, or the number of miles (m)traveled per gallon of gas (g) for each trip. Which driverwent the farthest on one gallon of gas?

Accepted Solution

A:
Answer:Andy went as furthest as possible with a gallon of gasolineStep-by-step explanation:Letm ----> the distance in milesg ----> the number of gallons of gasstep 1Kelley's MileageFind the slope of the linear function of Kelley's Mileagewe have the points(0,0) and (20,50)[tex]slope=(50-0)/(20-0)\\slope=2.5\ miles/gallon[/tex]the linear equation is[tex]m=2.5g[/tex]step 2Andy's MileageFind the slope of the linear function of Andy's Mileagewe have the points(15,78.75) and (30,157.5)[tex]slope=(157.5-78.75)/(30-15)\\slope=5.25\ miles/gallon[/tex]the linear equation is[tex]m=5.25g[/tex]step 3Rick's Mileagewe have[tex]m=4.8g[/tex]thereforethe slope is [tex]4.8\ miles/gallon[/tex]step 4Compare the slopes[tex]5.25\ miles/gallon > 4.8\ miles/gallon > 2.5\ miles/gallon[/tex]thereforeAndy went as furthest as possible with a gallon of gasoline